1
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

A normal is drawn at the point $$P$$ to the circle $$x^2+y^2=25$$, which is inclined at $$45^{\circ}$$ with the straight line $$y=6$$. Then, the point lies on the straight line

A
$$y=x$$
B
$$y=-x$$
C
$$y=\sqrt{3} x$$
D
$$\sqrt{3} y=x$$
2
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

If a tangent to the circle $$x^2+y^2=1$$ intersect the co-ordinate axes at distinct points $$P$$ and $$Q$$, then the locus of the mid-point of $$P Q$$ is

A
$$x^2+y^2-2 x y=0$$
B
$$x^2+y^2-2 x^2 y^2=0$$
C
$$x^2+y^2-4 x^2 y^2=0$$
D
$$x^2+y^2-16 x^2 y^2=0$$
3
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

The locus of the mid-point of the chord if contact of tangents drawn from points lying on the straight line $$4x - 5y = 20$$ to the circle $${x^2} + {y^2} = 9$$ is

A
$$20({x^2} + {y^2}) - 36x + 45y = 0$$
B
$$20({x^2} + {y^2}) + 36x - 45y = 0$$
C
$$36({x^2} + {y^2}) - 20x + 45y = 0$$
D
$$36({x^2} + {y^2}) + 20x - 45y = 0$$
4
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

Equation of circle which passes through the points (1, $$-$$2) and (3, $$-$$4) and touch the X-axis is

A
x2 + y2 + 6x + 2y + 9 = 0
B
x2 + y2 + 10x + 20y + 25 = 0
C
x2 + y2 + 6x + 4y + 9 = 0
D
None of the above
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