A uniform metallic wire having resistance $4 \Omega$ is bent to form a square loop (ABCD) (see figure). A resistance of $2 \Omega$ is connected between points $B$ and $D$ and a battery of 2 V is connected across points $A$ and $C$ as shown in the figure. Now the value of current $(l)$ is :

2 A
8 A
4.5 A
4 A
A 100-turn closely wound circular coil of radius 5 cm has a magnetic field of $3.14 \times 10^{-3} \mathrm{~T}$ at its centre. The current flowing through the coil, and the magnitude of the magnetic moment of this coil are, respectively :
(Take $\mu_0=4 \pi \times 10^{-7} \mathrm{~T} \mathrm{~m} / \mathrm{A}$ )
$2 \mathrm{~A}, 10 \mathrm{~A} \mathrm{~m}^2$
$2.5 \mathrm{~A}, 20 \mathrm{~A} \mathrm{~m}^2$
$2 \mathrm{~A}, 4 \mathrm{~A} \mathrm{~m}^2$
$2.5 \mathrm{~A}, 2 \mathrm{~A} \mathrm{~m}^2$
A rectangular wire loop of sides 8 cm and 3 cm with a small cut, is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the plane of the loop. The emf developed across the cut, if the velocity of the loop is $2 \mathrm{~cm} \mathrm{~s}^{-1}$, in a direction normal to the shorter side of the loop, will be :
$4.8 \times 10^{-4}$ volt
$1.2 \times 10^{-4}$ volt
$1.3 \times 10^{-4}$ volt
$1.8 \times 10^{-4}$ volt
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