1
NEET 2022 Phase 2
MCQ (Single Correct Answer)
+4
-1

Match the reagents (List-I) with the product (List-II) obtained from phenol.

List-I
List-II
(a) (i) NaOH (ii) CO$$_2$$ (iii) H$$^ + $$ (i) Benzoquinone
(b) (i) Aqueous NaOH + CHCl$$_3$$ (ii) H$$^ + $$ (ii) Benzene
(c) Zn dust, $$\Delta$$ (iii) Salicyl aldehyde
(d) Na$$_2$$Cr$$_2$$O$$_7$$, H$$_2$$SO$$_4$$ (iv) Salicylic acid

Choose the correct answer from the options given below :

A
(a) - (iv), (b) - (ii), (c) - (i), (d) - (iii)
B
(a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
C
(a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
D
(a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)
2
NEET 2022 Phase 2
MCQ (Single Correct Answer)
+4
-1

The correct order of bond angles in the following compounds/species is :

A
CO2 < NH3 < H2O < $$\mathop {\mathrm{N{H_4}}}\limits^ + $$
B
H2O < NH3 < $$\mathop {\mathrm{N{H_4}}}\limits^ + $$ < CO2
C
H2O < $$\mathop {\mathrm{N{H_4}}}\limits^ + $$ < NH3 < CO2
D
H2O < $$\mathop {\mathrm{N{H_4}}}\limits^ + $$ = NH3 < CO2
3
NEET 2022 Phase 2
MCQ (Single Correct Answer)
+4
-1

Match List-I with List-II :

List-I
(Reaction)
List-II
(Product formed)
(a) Gabriel synthesis (i) Benzaldehyde
(b) Kolbe synthesis (ii) Ethers
(c) Williamson synthesis (iii) Primary amines
(d) Etard reaction (iv) Salicylic acid

Choose the correct answer from the options given below :

A
(a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)
B
(a) - (iii), (b) - (i), (c) - (ii), (d) - (iv)
C
(a) - (ii), (b) - (iii), (c) - (i), (d) - (iv)
D
(a) - (iv), (b) - (iii), (c) - (i), (d) - (ii)
4
NEET 2022 Phase 2
MCQ (Single Correct Answer)
+4
-1

If first ionization enthalpies of elements X and Y are 419 kJ mol$$-$$1 and 590 kJ mol$$-$$1, respectively and second ionization enthalpies of X and Y are 3069 kJ mol$$-$$1 and 1145 kJ mol$$-$$1, respectively. Then correct statement is :

A
Both X and Y are alkaline earth metals
B
X is an alkali metal and Y is an alkaline earth metal
C
X is an alkaline earth metal and Y is an alkali metal
D
Both X and Y are alkali metals
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