1
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
Power dissipated in an LCR series circuit connected to an A.C. source of emf $$\varepsilon $$ is
A
$${{{\varepsilon ^2}\sqrt {{R^2} + {{\left( {L\omega - {1 \over {\omega }}} \right)}^2}} } \over R}$$
B
$${{{\varepsilon ^2}\sqrt {{R^2} + {{\left( {L\omega - {1 \over {C\omega }}} \right)}^2}} } \over R}$$
C
$${{{\varepsilon ^2}R} \over {\sqrt {{R^2} + {{\left( {L - {1 \over {C\omega }}} \right)}^2}} }}$$
D
$${{{\varepsilon ^2}R} \over {\left[ {{R^2} + {{\left( {L\omega - {1 \over {C\omega }}} \right)}^2}} \right]}}$$
2
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
See the electrical circuit shown in this figure. Which of the following equations is a correct equation for it ?

AIPMT 2009 Physics - Current Electricity Question 84 English
A
$${\varepsilon _2} - {i_2}{r_2} - {\varepsilon _1} - {i_1}{r_1} = 0$$
B
$$ - {\varepsilon _2} - \left( {{i_1} + {i_2}} \right)R + {i_2}{r_2} = 0$$
C
$${\varepsilon _1} - \left( {{i_1} + {i_2}} \right)R + {i_1}{r_1} = 0$$
D
$${\varepsilon _1} - \left( {{i_1} + {i_2}} \right)R - {i_1}{r_1} = 0$$
3
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
The mean free path of electrons in a metal is 4 $$ \times $$ 10$$-$$8 m. The electric field which can give on an average 2 eV energy to an electron in the metal will be in units V/m
A
$$5 \times {10^{ - 11}}$$
B
8 $$ \times $$ 10$$-$$11
C
5 $$ \times $$ 107
D
8 $$ \times $$ 107
4
AIPMT 2009
MCQ (Single Correct Answer)
+4
-1
A bar magnet having a magnetic moment of 2 $$ \times $$ 104 J T$$-$$1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 $$ \times $$ 10$$-$$4 T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60o from the field is
A
12 J
B
6 J
C
2 J
D
0.6 J