1
AIPMT 2007
MCQ (Single Correct Answer)
+4
-1
Charges +q and $$-$$q are placed at points A and B respectively which are a distance 2L apart, C is the midnight between A and B. The work done in moving a charge + Q along the semicircle CRD is

AIPMT 2007 Physics - Electrostatics Question 41 English
A
$${{qQ} \over {2\pi {\varepsilon _0}L}}$$
B
$${{qQ} \over {6\pi {\varepsilon _0}L}}$$
C
$$-$$ $${{qQ} \over {6\pi {\varepsilon _0}L}}$$
D
$${{qQ} \over {4\pi {\varepsilon _0}L}}$$
2
AIPMT 2007
MCQ (Single Correct Answer)
+4
-1
A hollow cylinder has a charge q coulomb within it. If $$f$$ is the electric flux in units of voltmeter associated with the curved surface B, the flux linked with the plane surface A in units of V-m will be

AIPMT 2007 Physics - Electrostatics Question 42 English
A
$${q \over {2{\varepsilon _0}}}$$
B
$${\phi \over 3}$$
C
$${q \over {{\varepsilon _0}}} - \phi $$
D
$${1 \over 2}\left( {{q \over {{\varepsilon _0}}} - \phi } \right)$$
3
AIPMT 2007
MCQ (Single Correct Answer)
+4
-1
Three point charges +q, $$-$$ 2q and + q are placed at points (x = 0, y = a, z = 0), (x = 0, y = 0, z = 0) and (x = $$a$$, y = 0, z = 0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are
A
$$\sqrt 2 qa$$ along the line joining points (x = 0, y = 0, z = 0) and (x = $$a$$, y = a, z = 0)
B
q$$a$$ along the line joining points (x = 0, y = 0, z = 0) and (x = $$a$$, y = a, z = 0)
C
$$\sqrt 2 qa$$ along +x direction
D
$$\sqrt 2 qa$$ along +y direction.
4
AIPMT 2007
MCQ (Single Correct Answer)
+4
-1
In the following circuit, the output Y for all possible inputs A and B is expressed by the truth table.

AIPMT 2007 Physics - Semiconductor Electronics Question 62 English
A
$$\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 1 \cr 1 & 0 & 1 \cr 1 & 1 & 0 \cr } $$
B
$$\matrix{ A & B & Y \cr 0 & 0 & 1 \cr 0 & 1 & 0 \cr 1 & 0 & 0 \cr 1 & 1 & 0 \cr } $$
C
$$\matrix{ A & B & Y \cr 0 & 0 & 0 \cr 0 & 1 & 1 \cr 1 & 0 & 1 \cr 1 & 1 & 1 \cr } $$
D
$$\matrix{ A & B & Y \cr 0 & 0 & 0 \cr 0 & 1 & 0 \cr 1 & 0 & 0 \cr 1 & 1 & 1 \cr } $$
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