1
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider the following carbocations.

TG EAPCET 2024 (Online) 11th May Morning Shift Chemistry - General Organic Chemistry Question 1 English

Arrange the above carbocations in the order of decreasing stability

A
I $ > $ III $ > $ IV $ > $ II $ > $ V
B
V $ > $ II $ > $ IV $ > $ III $ > $ I
C
V $ > $ II $ > $ III $ > $ I $ > $ IV
D
II $ > $ III $ > $ IV $ > $ V $ > $ I
2
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider the following reaction sequence

$ \text { 2-methylpropane } \xrightarrow{\mathrm{KMnO}_{4}} X \xrightarrow[358 \mathrm{~K}]{20 \% \mathrm{H}_3 \mathrm{PO}_4} Y \xrightarrow[\text { (ii) } \mathrm{Zn} / \mathrm{H}_{2} \mathrm{O}]{\text { (i) } \mathrm{O}_{3}} A+B \text {. } $

What are $A$ and $B$ ?

A
$\mathrm{CH}_{3} \mathrm{CH}=\mathrm{O}, \mathrm{CH}_{3} \mathrm{CH}=\mathrm{O}$
B
$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}, \mathrm{CH}_{2}=\mathrm{O}$
C
$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}, \mathrm{CH}_{3} \mathrm{CH}=\mathrm{O}$
D
$\mathrm{CH}_{3} \mathrm{CH}=\mathrm{O}, \mathrm{CH}_{2}=\mathrm{O}$
3
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Identify the end product $(Z)$ in the sequence of the following reactions.

TG EAPCET 2024 (Online) 11th May Morning Shift Chemistry - Aldehyde and Ketone Question 1 English

A

TG EAPCET 2024 (Online) 11th May Morning Shift Chemistry - Aldehyde and Ketone Question 1 English Option 1

B
TG EAPCET 2024 (Online) 11th May Morning Shift Chemistry - Aldehyde and Ketone Question 1 English Option 2
C

TG EAPCET 2024 (Online) 11th May Morning Shift Chemistry - Aldehyde and Ketone Question 1 English Option 3

D

TG EAPCET 2024 (Online) 11th May Morning Shift Chemistry - Aldehyde and Ketone Question 1 English Option 4

4
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In bcc lattice containing $X$ and $Y$ type of atoms, $X$ type of atoms are present at the corners and $Y$ type of atoms are present at the centers. In its unit cell, if three atoms are missing in the corners, the formula of the compound is
A
$X_{5} Y_{8}$
B
$X_{8} Y_{5}$
C
$X_{3} Y_{5}$
D
$X_{5} Y_{3}$
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