1
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

0.592 g of copper is deposited in 60 minutes by passing

0.5 A current through a solution of copper (II) sulphate. The electro chemical equivalent of copper (II) (in $\mathrm{gC}^{-1}$ ) is

( $F=96500 \mathrm{C} \mathrm{mol}^{-1}$ )

A
$3.3 \times 10^{-3}$
B
$3.3 \times 10^{-4}$
C
$6.6 \times 10^{-3}$
D
$6.6 \times 10^{-4}$
2
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For the gaseous reaction, $\mathrm{N}_{2} \mathrm{O}_{5} \longrightarrow 2 \mathrm{NO}_{2}+\frac{1}{2} \mathrm{O}_{2}$

the rate can be expressed as

$ \begin{array}{l} -\frac{d\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right]}{d t}=K_{1}\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right] \\\\ +\frac{d\left[\mathrm{NO}_{2}\right]}{d t}=K_{2}\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right] \\\\ +\frac{d\left[\mathrm{O}_{2}\right]}{d t}=K_{3}\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right] \end{array} $

The correct relation between $K_{1}, K_{2}$ and $K_{3}$

A
$K_{1}=2 K_{2}=4 K_{3}$
B
$2 K_{1}=K_{2}=4 K_{3}$
C
$2 K_{1}=3 K_{2}=4 K_{3}$
D
$4 K_{1}=2 K_{2}=K_{3}$
3
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Match the following

List I (Industrial process) List II (Catalyst used)
A Ostwald's process I $\mathrm{CuCl}_2$
B Haber's process II Zeolites
C Deacon's process III Pt gauge
D Cracking of hydrocarbons IV Fe

The correct answer is

A
$A-$ II, $B-I, C-I V, D-$ III
B
$A-$ IV, $B-I, C-I I, D-1 I I$
C
$A-$ III, $B-$ IV, $C-I I, D-1$
D
$A-$ III, $B-$ IV, $C-I, D-I I$
4
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
Copper matte is mixture of
A
oxides of Cu and Fe
B
carbonates of Cu and Fe
C
sulphides of Cu and Fe
D
silicates of Cu and Fe
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