1
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The general solution of the differential equation $\left(6 x^{2}-2 x y-18 x+3 y\right) d x-\left(x^{2}-3 x\right) d y=0$ is
A
$2 x^{3}-x^{2} y-9 x^{2}+3 x y+C=0$
B
$4 x^{3}-2 x^{2} y-6 x^{2}+6 x y+C=0$
C
$2 x^{2}-4 x y-y^{2}-x+3 y+C=0$
D
$3 x^{2}+5 x y-2 y^{2}-4 x-2 y+C=0$
2
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The range of gravitational forces is
A
$10^{-15} \mathrm{~m}$
B
$10^{-39} \mathrm{~m}$
C
infinity
D
$10^{-2} \mathrm{~m}$
3
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
In a simple pendulum experiment for the determination of acceleration due to gravity, the error in the measurement of the length of the pendulum is $1 \%$ and the error in the measurement of the time period is $2 \%$. The error in the estimation of acceleration due to gravity is
A
$1 \%$
B
$3 \%$
C
$4 \%$
D
$5 \%$
4
TG EAPCET 2024 (Online) 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0
The position $x$ (in metre) of a particle moving along a straight line is given by $x=t^{3}-12 t+3$, where $t$ is time (in second). The acceleration of the particle when its velocity becomes $15 \mathrm{~ms}^{-1}$ is
A
$15 \mathrm{~ms}^{-2}$
B
$24 \mathrm{~ms}^{-2}$
C
$18 \mathrm{~ms}^{-2}$
D
$12 \mathrm{~ms}^{-2}$
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