1
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The probability mass function of a random variable X is given by
$P(X = x) = \dfrac{{}^{5}C_x}{2^5}$, for $x = 0, 1, 2, 3, 4, 5$ and $= 0$, otherwise.
Then which of the following is correct?
A
$p(x \leq 2) = p(x \geq 3)$
B
$p(x \leq 2) > p(x \geq 3)$
C
$p(x \leq 2) < p(x \geq 3)$
D
$p(x \leq 2) = 2p(x \geq 3)$
2
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If events A and B are such that $P(A) = \dfrac{1}{4}$, $P(A \cap B) = \dfrac{1}{10}$ and $P(A/B) = 2P(B/A)$ then $P(B) = $...........
A
$\dfrac{1}{2}$
B
$\dfrac{1}{5}$
C
$\dfrac{1}{8}$
D
$\dfrac{2}{5}$
3
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
A quantity P is related as $X^{-2}Y^{-3/2}Z^{2/5}$ where X,Y,Z are independent parameters which have fractional errors of $0.1, 0.2$ and $0.5$ respectively in measurement. The maximum fractional error in P is
A
$0.7$
B
$0.1$
C
$0.8$
D
$0.6$
4
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The vectors $(\vec{A} + \vec{B})$ and $(\vec{A} - \vec{B})$ are perpendicular to each other. This is possible under the condition
A
$|\vec{A}| = |\vec{B}|$
B
$\vec{A} \cdot \vec{B} = 0$
C
$\vec{A} \times \vec{B} = 0$
D
$\vec{A} \cdot \vec{B} = 1$

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