1
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let $x_0$ be the point of local maxima of $f(x) = \bar{a} \cdot (\bar{b} \times \bar{c})$ where $\bar{a} = x\hat{i} - 2\hat{j} + 3\hat{k}, \bar{b} = -2\hat{i} + x\hat{j} - \hat{k}$ and $\bar{c} = 7\hat{i} - 2\hat{j} + x\hat{k}$ then the value of $\bar{a} \cdot \bar{c}$ at $x = x_0$ is
A
$26$
B
$0$
C
$-15$
D
$-26$
2
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The parallelopiped is determined by vectors $\bar{a} = -2\hat{i} + 5\hat{j} + 3\hat{k}$, $\bar{b} = \hat{i} + 3\hat{j} - 2\hat{k}$, $\bar{c} = -3\hat{i} + \hat{j} + 4\hat{k}$. The altitude of parallelopiped on the parallelogram base determined by vectors $\bar{b}$ and $\bar{c}$ is
A
$\dfrac{2\sqrt{3}}{5}$
B
$\dfrac{2}{5}$
C
$12$
D
$\dfrac{5\sqrt{3}}{2}$
3
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The vector equation of the plane passing through the point $A(-2, 7, 5)$ and parallel to the vectors $4\hat{i} - \hat{j} + 3\hat{k}$ and $\hat{i} + \hat{j} + \hat{k}$ is ...
A
$\bar{r} \cdot (-2\hat{i} + 7\hat{j} + 5\hat{k}) = 26$
B
$\bar{r} \cdot (4\hat{i} - \hat{j} + 3\hat{k}) = 27$
C
$\bar{r} \cdot (4\hat{i} - \hat{j} + 5\hat{k}) = 26$
D
$\bar{r} \cdot (-4\hat{i} - \hat{j} + 5\hat{k}) = 26$
4
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The point of intersection of the two lines $\dfrac{x-3}{3} = \dfrac{y-3}{-1}, z - 1 = 0$ and $\dfrac{x-6}{2} = \dfrac{z-1}{3}, y - 2 = 0$ is....
A
$(0, 0, 0)$
B
$(1, 2, 6)$
C
$(3, -1, 0)$
D
$(6, 2, 1)$

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