1
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The tangent to the curve $y^2 - xy + 9 = 0$ is vertical when
A
$y = 0$
B
$y = \pm\sqrt{3}$
C
$y = \dfrac{1}{2}$
D
$y = \pm 3$
2
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of $k$ such that the function $f(x) = \sin x - \cos x - kx + b$ is strictly decreasing for all real $x$ is
A
$k < 1$
B
$k > 1$
C
$k < \sqrt{2}$
D
$k > \sqrt{2}$
3
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int \dfrac{\sin x}{\sin 4x} dx = $
A
$\dfrac{1}{4\sqrt{2}}\log\left|\dfrac{1 + \sqrt{2}\sin x}{1 - \sqrt{2}\sin x}\right| + \dfrac{1}{4}\log|\sec x + \tan x| + c$
B
$\dfrac{1}{4\sqrt{2}}\log\left|\dfrac{1 + \sqrt{2}\sin x}{1 - \sqrt{2}\sin x}\right| - \dfrac{1}{4}\log|\sec x + \tan x| + c$
C
$\dfrac{1}{4\sqrt{2}}\log\left|\dfrac{1 - \sqrt{2}\sin x}{1 + \sqrt{2}\sin x}\right| + \dfrac{1}{4}\log|\sec x + \tan x| + c$
D
$\dfrac{1}{4\sqrt{2}}\log\left|\dfrac{1 - \sqrt{2}\sin x}{1 + \sqrt{2}\sin x}\right| - \dfrac{1}{4}\log|\sec x + \tan x| + c$
4
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
$\int \sqrt{4^x(4^x + 4)}\, dx = \cdots$
A
$\dfrac{1}{\log 2}\left[\dfrac{2^x}{2}\sqrt{4^x + 4} + 2\log|2^x + \sqrt{4^x + 4}|\right] + c$
B
$\dfrac{2^x}{2}\sqrt{4^x + 4} + 2\log|2^x + \sqrt{4^x + 4}| + c$
C
$\dfrac{1}{\log 2}\left[\dfrac{2^x}{2}\sqrt{4^x + 4} + \log|2^x + \sqrt{4^x + 4}|\right] + c$
D
$\left[\dfrac{2^x}{\log 4}\sqrt{4^x + 4} + \log|2^x + \sqrt{4^x + 4}|\right] + c$

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