MHT CET 2026 11th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

If $X \sim B(n, p)$, then the value of $\dfrac{P(X = k)}{P(X = k - 1)}$ is

$\left(\dfrac{n - k}{k}\right)\dfrac{p}{q}$

$\left(\dfrac{n - k + 1}{k}\right)\dfrac{p}{q}$

$\left(\dfrac{n - k}{k - 1}\right)\dfrac{p}{q}$

$\left(\dfrac{n - k + 1}{k - 1}\right)\dfrac{p}{q}$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

A player tosses two fair coins, he wins Rs. $5$ if two heads appear, Rs. $3$ if one head appears and Rs. $2$ if no head appears, then the variance of the winning amount is

$1.1875$

$1.8175$

$1.1785$

$1.8157$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

The probability mass function of a random variable X is given by
$P(X = x) = \dfrac{{}^{5}C_x}{2^5}$, for $x = 0, 1, 2, 3, 4, 5$ and $= 0$, otherwise.
Then which of the following is correct?

$p(x \leq 2) = p(x \geq 3)$

$p(x \leq 2) > p(x \geq 3)$

$p(x \leq 2) < p(x \geq 3)$

$p(x \leq 2) = 2p(x \geq 3)$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

If events A and B are such that $P(A) = \dfrac{1}{4}$, $P(A \cap B) = \dfrac{1}{10}$ and $P(A/B) = 2P(B/A)$ then $P(B) = $...........

$\dfrac{1}{2}$

$\dfrac{1}{5}$

$\dfrac{1}{8}$

$\dfrac{2}{5}$