1
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In biprism experiment, the $4^{th}$ dark band is formed opposite to one of the slits. The wavelength of light used is (D=distance between source and screen, d= the distance between the slits)
A
$\dfrac{d^2}{9D}$
B
$\dfrac{d^2}{11D}$
C
$\dfrac{d^2}{14D}$
D
$\dfrac{d^2}{7D}$
2
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
In Young's double slit experiment, in an interference pattern, a minimum is observed exactly in front of one slit. The distance between the two coherent sources is 'd' and 'D' is the distance between source and screen. The possible wavelengths used are inversely proportional to
A
$D, 2D, 3D, \ldots$
B
$D, 3D, 5D, \ldots$
C
$\dfrac{1}{D}, \dfrac{2}{D}, \dfrac{3}{D}, \ldots$
D
$\dfrac{1}{D^2}, \dfrac{2}{D^2}, \dfrac{3}{D^2}, \ldots$
3
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
Converging lens of telescope $5$ cm in diameter has focal length $25$ cm. In the focal plane of the lens the distance between the centres of the Fraunhofer diffraction pattern is (wavelength of light used = $5000$ Å, Rayleigh's criterion is satisfied)
A
$25000$ Å
B
$28000$ Å
C
$30500$ Å
D
$32000$ Å
4
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
Photoelectrons are emitted from two similar metal plates when wavelengths $\lambda_1$ and $\lambda_2$ are incident on them ($\lambda_1 = 1.5\lambda_2$). If maximum kinetic energy of emitted photoelectrons is $E_1$ and $E_2$ respectively then
A
$E_1 < 2E_2/3$
B
$E_1 = 2E_2/3$
C
$E_1 = E_2/3$
D
$E_1 = 2E_2$

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