MHT CET 2026 11th April Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

A source of sound is moving towards a stationary observer with velocity '$V_S$' and then moves away with velocity '$V_S$'. Assume that medium through which the sound waves travel is at rest. If 'V' is the velocity of sound and 'n' is the frequency emitted by the source then the difference between the apparent frequencies heard by the observer is

$\dfrac{2nVV_s}{V^2 - V_s^2}$

$\dfrac{nVV_s}{V^2 - V_s^2}$

$\dfrac{nVV_s}{V_s^2 + V^2}$

$\dfrac{2nVV_s}{V_s^2 + V^2}$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

If the radius of the spherical Gaussian surface is increased then the electric flux due to a point charge enclosed by the surface

increases

remains unchanged

is zero

decreases

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

The earth is assumed to be a charged conducting sphere having volume 'V' and surface area 'A'. The capacitance of the earth in free space is ($\epsilon_0$ = permittivity of free space)

$2\pi \epsilon_0 V/A$

$4\pi \epsilon_0 V/A$

$8\pi \epsilon_0 V/A$

$12\pi \epsilon_0 V/A$

MHT CET 2026 11th April Evening Shift

MCQ (Single Correct Answer)

-0

Initially, 'n' identical capacitors are joined in parallel, are charged to potential 'V'. Now they are separated and joined in series. Then

potential difference and total energy of the combination remain the same

potential difference remains the same and energy increases 'n' times

potential difference becomes 'nv' and energy remains the same

potential difference is 'nv' and energy increases 'n' times.