1
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The parallelopiped is determined by vectors $\bar{a} = -2\hat{i} + 5\hat{j} + 3\hat{k}$, $\bar{b} = \hat{i} + 3\hat{j} - 2\hat{k}$, $\bar{c} = -3\hat{i} + \hat{j} + 4\hat{k}$. The altitude of parallelopiped on the parallelogram base determined by vectors $\bar{b}$ and $\bar{c}$ is
A
$\dfrac{2\sqrt{3}}{5}$
B
$\dfrac{2}{5}$
C
$12$
D
$\dfrac{5\sqrt{3}}{2}$
2
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The vector equation of the plane passing through the point $A(-2, 7, 5)$ and parallel to the vectors $4\hat{i} - \hat{j} + 3\hat{k}$ and $\hat{i} + \hat{j} + \hat{k}$ is ...
A
$\bar{r} \cdot (-2\hat{i} + 7\hat{j} + 5\hat{k}) = 26$
B
$\bar{r} \cdot (4\hat{i} - \hat{j} + 3\hat{k}) = 27$
C
$\bar{r} \cdot (4\hat{i} - \hat{j} + 5\hat{k}) = 26$
D
$\bar{r} \cdot (-4\hat{i} - \hat{j} + 5\hat{k}) = 26$
3
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The point of intersection of the two lines $\dfrac{x-3}{3} = \dfrac{y-3}{-1}, z - 1 = 0$ and $\dfrac{x-6}{2} = \dfrac{z-1}{3}, y - 2 = 0$ is....
A
$(0, 0, 0)$
B
$(1, 2, 6)$
C
$(3, -1, 0)$
D
$(6, 2, 1)$
4
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the centroid of a tetrahedron $OABC$ is $(1, 2, -1)$, where O is the origin, $A(a, 2, 3), B(1, b, 2), C(2, 1, c)$ are the other vertices, then the distance of the point $P(a, b, c)$ from the origin is...
A
$42$ units
B
$\sqrt{107}$ units
C
$25$ units
D
$15$ units

MHT CET Papers

All year-wise previous year question papers