1
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the lines $\dfrac{x-1}{2} = \dfrac{y+1}{3} = \dfrac{z-1}{4}$ and $\dfrac{x-3}{1} = \dfrac{y-c}{2} = \dfrac{z}{1}$ intersect, then the radius of circle $x^2 + y^2 - 4x + 10y + c = 0$ is
A
$\dfrac{9}{\sqrt{2}}$
B
$\dfrac{9}{2}$
C
$\dfrac{7}{\sqrt{2}}$
D
$\dfrac{7}{2}$
2
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The corner points of the feasible region determined by a system of linear constraints are $(0, 3), (1, 1)$ and $(3, 0)$. If the objective function is $z = px + qy$, where $p, q > 0$, then the condition on p and q such that the minimum of z occurs at both $(3, 0)$ and $(1, 1)$ is _____
A
$p = 3q$
B
$3p = q$
C
$p = \dfrac{q}{2}$
D
$p = 2q$
3
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $X \sim B(n, p)$, then the value of $\dfrac{P(X = k)}{P(X = k - 1)}$ is
A
$\left(\dfrac{n - k}{k}\right)\dfrac{p}{q}$
B
$\left(\dfrac{n - k + 1}{k}\right)\dfrac{p}{q}$
C
$\left(\dfrac{n - k}{k - 1}\right)\dfrac{p}{q}$
D
$\left(\dfrac{n - k + 1}{k - 1}\right)\dfrac{p}{q}$
4
MHT CET 2026 11th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
A player tosses two fair coins, he wins Rs. $5$ if two heads appear, Rs. $3$ if one head appears and Rs. $2$ if no head appears, then the variance of the winning amount is
A
$1.1875$
B
$1.8175$
C
$1.1785$
D
$1.8157$

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