MHT CET 2024 11th May Morning Shift | MHT CET Year Wise Previous Years Questions

A particle performs linear S.H.M. at a particular instant, velocity of the particle is ' $u$ ' and acceleration is ' $\mathrm{a}_1$ ' while at another instant velocity is ' V ' and acceleration is ' $a_2$ ' $\left(0

$\frac{v^2-u^2}{a_1-a_2}$

$\frac{v^2+u^2}{a_1+a_2}$

$\frac{u^2+v^2}{a_1-a_2}$

$\frac{u^2-V^2}{a_1+a_2}$

MHT CET 2024 11th May Morning Shift

MCQ (Single Correct Answer)

-0

For the velocity-time graph shown in the figure below, the distance covered by the body in last two second of its motion is ' $\mathrm{S}_1$ '. What is the ratio of ' $\mathrm{S}_1$ ' to the total distance covered by it

MHT CET 2024 11th May Morning Shift Physics - Motion Question 2 English

$\frac{1}{2}$

$\frac{1}{4}$

$\frac{1}{3}$

$\frac{2}{3}$

MHT CET 2024 11th May Morning Shift

MCQ (Single Correct Answer)

-0

The coefficient of mutual induction is 2 H and induced e.m.f. across secondary is 2 kV Current in the primary is reduced from 6 A to 3 A . The time required for the change of current is

$3 \times 10^{-3} \mathrm{~s}$

$3 \times 10^{-2} \mathrm{~s}$

$6 \times 10^{-3} \mathrm{~s}$

$3 \times 10^{-2} \mathrm{~s}$

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