1
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle performs linear S.H.M. at a particular instant, velocity of the particle is ' $u$ ' and acceleration is ' $\mathrm{a}_1$ ' while at another instant velocity is ' V ' and acceleration is ' $a_2$ ' $\left(0

A
$\frac{v^2-u^2}{a_1-a_2}$
B
$\frac{v^2+u^2}{a_1+a_2}$
C
$\frac{u^2+v^2}{a_1-a_2}$
D
$\frac{u^2-V^2}{a_1+a_2}$
2
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

For the velocity-time graph shown in the figure below, the distance covered by the body in last two second of its motion is ' $\mathrm{S}_1$ '. What is the ratio of ' $\mathrm{S}_1$ ' to the total distance covered by it

MHT CET 2024 11th May Morning Shift Physics - Motion Question 5 English

A
$\frac{1}{2}$
B
$\frac{1}{4}$
C
$\frac{1}{3}$
D
$\frac{2}{3}$
3
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The coefficient of mutual induction is 2 H and induced e.m.f. across secondary is 2 kV Current in the primary is reduced from 6 A to 3 A . The time required for the change of current is

A
$3 \times 10^{-3} \mathrm{~s}$
B
$3 \times 10^{-2} \mathrm{~s}$
C
$6 \times 10^{-3} \mathrm{~s}$
D
$3 \times 10^{-2} \mathrm{~s}$
4
MHT CET 2024 11th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The work done in blowing a soap bubble of radius $R$ is $W_1$ at room temperature. Now the soap solution is heated. From the heated solution another soap bubble of radius 2 R is blown and the work done is $\mathrm{W}_2$. Then

A
$\mathrm{W}_2=0$
B
$\mathrm{W}_2=4 \mathrm{~W}_1$
C
$\mathrm{W}_2<4 \mathrm{~W}_1$
D
$\mathrm{W}_2=\mathrm{W}_1$
MHT CET Papers
EXAM MAP