1
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
A boy is running along a straight horizontal road with a constant speed $5 \mathrm{~ms}^{-1}$. While running he throws a stone with a velocity $30 \mathrm{~ms}^{-1}$ at an angle $60^{\circ}$ with the horizontal. Then the time of flight of the stone is: (Given $g=10 \mathrm{~ms}^{-2}$ )
A
$3 \sqrt{2}$
B
$\frac{\sqrt{3}}{2}$
C
$4 \sqrt{3}$
D
$3 \sqrt{3}$
2
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
In a pure inductive circuit, a sinusoidal voltage $V(t)=200 \sin 250 t$ is applied to a pure inductance of $\mathrm{L}=0.02 \mathrm{H}$. The current through the coil is:
A
$40 \sin \left[250 t-\frac{\pi}{2}\right]$
B
$40 \cos \left[250 t-\frac{\pi}{2}\right]$
C
$40 \sin \left[250 t+\frac{\pi}{2}\right]$
D
$40 \cos \left[250 t+\frac{\pi}{2}\right]$
3
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
In to a vessel containing pure water a clean glass tube of radius $3.6 \times 10^{-4} \mathrm{~m}$ is held vertically with 12 cm of the tube above the water level. Now the capillary tube is moved down in to the water so that only 2 cm of its length is above the water surface. Angle of contact $\Theta$ at this position is (given surface tension of water $=7.2 \times 10^{-2} \mathrm{Nm}^{-1}$ and $g=10 \mathrm{~ms}^{-2}$ )
A
$\Theta=45^{\circ}$
B
$\Theta=30^{\circ}$
C
$\Theta=15^0$
D
$\Theta=60^{\circ}$
4
COMEDK 2025 Evening Shift
MCQ (Single Correct Answer)
+1
-0
A point marked on a ring of radius 2 cm is in contact with a horizontal plane. Now the ring is rolled forward half a revolution along the positive X - direction. Then the angle made by the displacement vector of the point with the X - axis is:
A
$\theta=\boldsymbol{\operatorname { t a n }}^{-\mathbf{1}}\left(\frac{\mathbf{2}}{\mathbf{3} \boldsymbol{\pi}}\right)$
B
$\boldsymbol{\theta}=\boldsymbol{\operatorname { t a n }}^{-\mathbf{1}}\left(\frac{\mathbf{2}}{\boldsymbol{\pi}}\right)$
C
$\theta=\tan ^{-1}\left(\frac{2 \pi}{3}\right)$
D
$\theta=\cot ^{-1}\left(\frac{2}{\pi}\right)$
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