1
GATE CSE 2007
MCQ (Single Correct Answer)
+2
-0.6
Consider the B+ tree in the adjoining figure, where each node has at most two keys and three links. GATE CSE 2007 Database Management System - File Structures and Indexing Question 12 English 1

Now the key K 50 is deleted from the B+ tree resulting after the two insertions made earlier. Consider the following statements about the B+ tree resulting after this deletion.

i) The height of the tree remains the same.

ii) The node GATE CSE 2007 Database Management System - File Structures and Indexing Question 12 English 2 (disregarding the links) is present in the tree.

iii) The root node remains unchanged (disregarding the links).

Which one of the following options is true ?
A
Statements (i) and (ii) are true
B
Statements (ii) and (iii) are true
C
Statements (iii) and (i) are true
D
All the statements are false
2
GATE CSE 2007
MCQ (Single Correct Answer)
+2
-0.6
Consider the following two transactions: T1 and T2.
T1: read (A);                  T2: read (B);
    read (B);                      read (A);
    if A = 0 then B ← B + 1;       if B ≠ 0 then A ← A - 1;
    write (B);                     write (A);
Which of the following schemes, using shared and exclusive locks, satisfy the requirements for strict two phase locking for the above transactions?
A
S1 : lockS(A); 	        S2 : lockS(B);
     read (A);               read (B);
     lockS(B);               lockS(A);
     read (B);               read (A);
     if A = 0                if B ≠ 0
     then B ← B + 1;        then A ← A - 1;
     write (B);              write (A);
     commit;                 commit;
     unlock (A);             unlock (B);
     unlock (B);             unlock (A);
B
S1 : lockX(A);          S2 : lockX(B);
     read (A);               read (B);
     lockX(B);               lockX(A);
     read (B);               read (A);
     if A = 0                if B ≠ 0
     then B ← B + 1;        then A ← A - 1;
     write (B);              write (A);
     unlock (A);             unlock (A);
     commit;                 commit;
     unlock (B);             unlock (A);
C
S1 : lockS(A);           S2 : lockS(B);
     read (A);                read (B);
     lockX(B);                lockX(A);
     read (B);                read (A);
     if A = 0                 if B ≠ 0
     then B ← B + 1;         then A ← A - 1;
     write (B);               write (A);
     unlock (A);              unlock (B);
     commit;                  commit;
     unlock (B);              unlock (A);
D
S1 : lockS(A);           S2 : lockS(B);
     read (A);                read (B);
     lockX(B);                lockX(A);
     read (B);                read (A);
     if A = 0                 if B ≠ 0
    then B ← B + 1;        then A ← A - 1;
     write (B);               write (A);                                                                                                     
     unlock (A);              unlock (A);
     unlock (B);              unlock (B);
     commit;                  commit;
3
GATE CSE 2007
MCQ (Single Correct Answer)
+2
-0.6
Consider the following schedules involving two transactions. Which one of the following statements is TRUE?

S1: r1(X); r1(Y); r2(Y); r2(X); w2(Y); w1(X);

S2: r1(X); r2(X); r2(Y); w2(Y); r1(Y); w1(X);

A
Both S1 and S2 are conflict serializable.
B
S1 is conflict serializable and S2 is not conflict serializable.
C
S1 is not conflict serializable and S2 is conflict serializable.
D
Both S1 and S2 are not conflict serializable.
4
GATE CSE 2007
MCQ (Single Correct Answer)
+2
-0.6
Consider the following relation schemas :

b-Schema = (b-name, b-city, assets)
a-Schema = (a-num, b-name, bal)
d-Schema = (c-name, a-number)

Let branch, account and depositor be respectively instances of the above schemas. Assume that account and depositor relations are much bigger than the branch relation.

Consider the following query:
Пc-nameb-city = “Agra” ⋀ bal < 0 (branch $$ \Join $$ (account $$ \Join $$ depositor))

Which one of the following queries is the most efficient version of the above query ?

A
Пc-namebal < 0b-city = “Agra” branch $$ \Join $$ account) $$ \Join $$ depositor)
B
Пc-nameb-city = “Agra”branch $$ \Join $$ (σbal < 0 account $$ \Join $$ depositor))
C
Пc-nameb-city = “Agra” branch $$ \Join $$ σb-city = “Agra” ⋀ bal < 0 account) $$ \Join $$ depositor)
D
Пc-nameb-city = “Agra” ⋀ bal < 0 account $$ \Join $$ depositor))
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