1
BITSAT 2023
+3
-1

The potential energy for a force field $$\mathbf{F}$$ is given by $$u(x, y)=\cos (x+y)$$. The force acting on a particle at position given by co-ordinates $$(0, \pi / 6)$$ is

A
$$\frac{-1}{\sqrt{2}}(\hat{\mathbf{i}}+\hat{\mathbf{j}})$$
B
$$\frac{1}{2}(\hat{\mathbf{i}}+\hat{\mathbf{j}})$$
C
$$\frac{1}{2} \hat{\mathbf{i}}+\frac{\sqrt{3}}{2} \hat{\mathbf{j}}$$
D
$$\frac{1}{2} \hat{i}-\frac{\sqrt{3}}{2} \hat{j}$$
2
BITSAT 2022
+3
-1

A machine gun fires 300 bullets per min if the mass of each bullet is 10 g and the velocity of the bullets is 600 ms$$-$$1, the power (in kW) of the gun is

A
43200
B
9
C
72
D
7.2
3
BITSAT 2021
+3
-1

A force F = a + bx acts on a particle in the x-direction where a and b are constants. The work done by this force during a displacement from x = 0 to x = d is

A
$$\left( {a + {{bd} \over 2}} \right)d$$
B
$$\left( {ad + {{bd} \over 2}} \right)$$
C
$$\left( {{{ad + bd} \over 2}} \right)$$
D
$$(ad + b){d \over 2}$$
4
BITSAT 2021
+3
-1

The bob of a pendulum of length 2 m lies at P, when it reaches Q, it losses 10% of its total energy due to air resistance.

The velocity of bob at Q is

A
6 m/s
B
1 m/s
C
2 m/s
D
8 m/s
EXAM MAP
Medical
NEET