BITSAT 2024 | Motion Question 1 | Physics

A projectile is projected with velocity of $ 40 \mathrm{~m} / \mathrm{s} $ at an angle $ \theta $ with the horizontal. If $ R $ be the horizontal range covered by the projectile and after $ t $ seconds, its inclination with horizontal becomes zero, then the value of $ \cot \theta $ is [Take, $ g=10 \mathrm{~m} / \mathrm{s}^{2} $ ]

$ \frac{R}{20 t^{2}} $

$ \frac{R}{10 t^{2}} $

$ \frac{5 R}{t^{2}} $

$ \frac{R}{t^{2}} $

BITSAT 2023

MCQ (Single Correct Answer)

-1

A boat crosses a river from part $$A$$ to part $$B$$, which are just on the opposite side. The speed of the water. $$v_\omega$$ and the of boat is $$v_B$$ relative to still water. Assume $$v_B=\sqrt{2} v_\omega$$. What is the time taken by the boat, if it has to cross the river directly on the $$A B$$ line ($$D=$$ width of the river) ?

$$\frac{2 D}{\sqrt{3} v_B}$$

$$\frac{\sqrt{3} D}{2 v_B}$$

$$\frac{D}{\sqrt{2} v_B}$$

$$\frac{\sqrt{2} D}{v_B}$$

BITSAT 2022

MCQ (Single Correct Answer)

-1

A projectile is projected with the velocity of $$(3\widehat i + 4\widehat j)$$ m/s. The horizontal range of the projectile will be

1.2 m

2.4 m

3.6 m

4.5 m

BITSAT 2021

MCQ (Single Correct Answer)

-1

A man walks in a straight line for 5 min with a velocity of 45 m/s. What is the speed with which he has to move in order to comeback to its original position in 1.5 min?

90 m/s

150 m/s

135 m/s

115 m/s

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