1
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

A force F = a + bx acts on a particle in the x-direction where a and b are constants. The work done by this force during a displacement from x = 0 to x = d is

A
$$\left( {a + {{bd} \over 2}} \right)d$$
B
$$\left( {ad + {{bd} \over 2}} \right)$$
C
$$\left( {{{ad + bd} \over 2}} \right)$$
D
$$(ad + b){d \over 2}$$
2
BITSAT 2021
MCQ (Single Correct Answer)
+3
-1

The bob of a pendulum of length 2 m lies at P, when it reaches Q, it losses 10% of its total energy due to air resistance.

BITSAT 2021 Physics - Work, Energy and Power Question 2 English

The velocity of bob at Q is

A
6 m/s
B
1 m/s
C
2 m/s
D
8 m/s
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