1
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
A force of $ F=0.5 \mathrm{~N} $ is applied on lower block as shown in figure. The work done by lower block on upper block for a displacement of 3 m of the upper block with respect to ground is (Take, $ g=10 \mathrm{~m} / \mathrm{s}^{2} $ )

BITSAT 2024 Physics - Work, Energy and Power Question 2 English

A
-05 J
B
0.5 J
C
2 J
D
-2 J
2
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
A pendulum of mass 1 kg and length $ l=1 \mathrm{~m} $ is released from rest at angle $ \theta=60^{\circ} $. The power delivered by all the forces acting on the bob at angle $ \theta=30^{\circ} $ will be (Take, $ g=10 \mathrm{~m} / \mathrm{s}^{2} $ )
A
13.4 W
B
$ 20.4 \mathrm{~W}^{\text {. }} $
C
24.6 W
D
zero
3
BITSAT 2024
MCQ (Single Correct Answer)
+3
-1
An ideal massless spring $ S $ can be compressed 1 m by a force of 100 N in equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined at $ 30^{\circ} $ to the horizontal. A 10 kg block $ M $ is released from rest at the top of the incline and is brought to rest momentarily after compressing the spring by 2 m . If $ g=10 \mathrm{~m} / \mathrm{s}^{2} $, what is the speed of mass just before it touches the spring?

BITSAT 2024 Physics - Work, Energy and Power Question 1 English

A
$ \sqrt{20} \mathrm{~m} / \mathrm{s} $
B
$ \sqrt{30} \mathrm{~m} / \mathrm{s} $
C
$ \sqrt{10} \mathrm{~m} / \mathrm{s} $
D
$ \sqrt{40} \mathrm{~m} / \mathrm{s} $
4
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

The potential energy for a force field $$\mathbf{F}$$ is given by $$u(x, y)=\cos (x+y)$$. The force acting on a particle at position given by co-ordinates $$(0, \pi / 6)$$ is

A
$$\frac{-1}{\sqrt{2}}(\hat{\mathbf{i}}+\hat{\mathbf{j}})$$
B
$$\frac{1}{2}(\hat{\mathbf{i}}+\hat{\mathbf{j}})$$
C
$$\frac{1}{2} \hat{\mathbf{i}}+\frac{\sqrt{3}}{2} \hat{\mathbf{j}}$$
D
$$\frac{1}{2} \hat{i}-\frac{\sqrt{3}}{2} \hat{j}$$
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