If $|x+5| \geq 10$, then

Let $f(x)=x-\frac{1}{x}$, then $f(-1)$ is

Let $f, g: R \rightarrow R$ be two functions defined as $f(x)=|x|+x$ and $g(x)=|x|-x \forall x \in R$. Then $(f \circ g)(x)$ for $x<0$ is

A is a set having 6 distinct elements. The number of distinct functions from $A$ to $A$ which are not bijections is