1
KCET 2025
MCQ (Single Correct Answer)
+1
-0
If $A$ and $B$ are two events such that $A \subset B$ and $P(B) \neq 0$, then which of the following is correct?
A
$\mathrm{P}(\mathrm{A} \mid \mathrm{B})=\frac{\mathrm{P}(\mathrm{B})}{\mathrm{P}(\mathrm{A})}$
B
$\mathrm{P}(\mathrm{A} \mid \mathrm{B})<\mathrm{P}(\mathrm{A})$
C
$\mathrm{P}(\mathrm{A} \mid \mathrm{B}) \geq \mathrm{P}(\mathrm{A})$
D
$\mathrm{P}(\mathrm{A})=\mathrm{P}(\mathrm{B})$
2
KCET 2025
MCQ (Single Correct Answer)
+1
-0

Meera visits only one of the two temples A and B in her locality. Probability that she visits temple A is $\frac{2}{5}$. If she visits temple $A, \frac{1}{3}$ is the probability that she meets her friend, whereas it is $\frac{2}{7}$ if she visits temple $B$. Meera met her friend at one of the two temples. The probability that she met her at temple B is

A
$\frac{7}{16}$
B
$\frac{5}{16}$
C
$\frac{3}{16}$
D
$\frac{9}{16}$
3
KCET 2024
MCQ (Single Correct Answer)
+1
-0

A die is thrown 10 times. The probability that an odd number will come up at least once is

A
$\frac{11}{1024}$
B
$\frac{1013}{1024}$
C
$\frac{1023}{1024}$
D
$\frac{1}{1024}$
4
KCET 2024
MCQ (Single Correct Answer)
+1
-0

A random variable $X$ has the following probability distribution:

$X$ 0 1 2
$P(X)$ 25/36 $k$ 1/36

If the mean of the random variable $X$ is $1 / 3$, then the variance is

A
$\frac{1}{18}$
B
$\frac{5}{18}$
C
$\frac{7}{18}$
D
$\frac{11}{18}$
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