NEET 2023 Manipur | NEET Year Wise Previous Years Questions

The viscous drag acting on a metal sphere of diameter $$1 \mathrm{~mm}$$, falling through a fluid of viscosity $$0.8 \mathrm{~Pa}$$ s with a velocity of $$2 \mathrm{~m} \mathrm{~s}^{-1}$$ is equal to :

$$15 \times 10^{-3} \mathrm{~N}$$

$$30 \times 10^{-3} \mathrm{~N}$$

$$1.5 \times 10^{-3} \mathrm{~N}$$

$$20 \times 10^{-3} \mathrm{~N}$$

NEET 2023 Manipur

MCQ (Single Correct Answer)

-1

If $$\mathrm{R}$$ is the radius of the earth and $$\mathrm{g}$$ is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be :

$$\frac{\pi \mathrm{RG}}{12 \mathrm{~g}}$$

$$\frac{3 \pi R}{4 g G}$$

$$\frac{3 g}{4 \pi R G}$$

$$\frac{4 \pi \mathrm{G}}{3 g R}$$

NEET 2023 Manipur

MCQ (Single Correct Answer)

-1

A copper wire of radius $$1 \mathrm{~mm}$$ contains $$10^{22}$$ free electrons per cubic metre. The drift velocity for free electrons when $$10 \mathrm{~A}$$ current flows through the wire will be (Given, charge on electron $$=1.6 \times 10^{-19} \mathrm{C}$$ ) :

$$\frac{6.25 \times 10^4}{\pi} \mathrm{ms}^{-1}$$

$$\frac{6.25}{\pi} \times 10^3 \mathrm{~ms}^{-1}$$

$$\frac{6.25}{\pi} \mathrm{ms}^{-1}$$

$$\frac{6.25 \times 10^5}{\pi} \mathrm{ms}^{-1}$$

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