1
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
Which of the following structures is the most preferred and hence of lowest energy for SO3?
A
AIPMT 2011 Mains Chemistry - Chemical Bonding and Molecular Structure Question 33 English Option 1
B
AIPMT 2011 Mains Chemistry - Chemical Bonding and Molecular Structure Question 33 English Option 2
C
AIPMT 2011 Mains Chemistry - Chemical Bonding and Molecular Structure Question 33 English Option 3
D
AIPMT 2011 Mains Chemistry - Chemical Bonding and Molecular Structure Question 33 English Option 4
2
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
Out of Syllabus
A bubble of air is underwater at temperature 15oC and the pressure 1.5 bar. If the bubble rises to the surface where the temperature is 25oC and the pressure is 1.0 bar, what will happen to the volume of the bubble?
A
Volume will become greater by a factor of 1.6.
B
Volume will become greater by a factor of 1.1
C
Volume will become smaller by a factor of 0.70
D
Volume will become greater by a factor of 2.5
3
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
Consider the following processes :

H (kJ/mol)
1/2A $$ \to $$ B +150
3B  $$ \to $$ 2C + D -125
E + A  $$ \to $$ 2D +350

For B + D $$ \to $$ E + 2C, $$\Delta $$H will be
A
525 kJ/mol
B
$$-$$175 kJ/mol
C
$$-$$ 325 kJ/mol
D
325 kJ/mol
4
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
In qualitative analysis, the metals of group I can be separated from other ions by precipitating them as chloride salts. A solution initially contains Ag+ and pb2+ at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl$$-$$ concentration is 0.10 M. What will the concentrations of Ag+ and Pb2+ be at equilibrium ?

(Ksp for AgCl = 1.8 $$ \times $$ 10$$-$$10, Ksp for PbCl2 = 1.7 $$ \times $$ 10$$-$$5)
A
[Ag+] = 1.8 $$ \times $$ 10$$-$$7 M, [Pb2+] = 1.7 $$ \times $$ 10$$-$$6 M
B
[Ag+] = 1.8 $$ \times $$ 10$$-$$11 M, [Pb2+] = 8.5 $$ \times $$ 10$$-$$5 M
C
[Ag+] = 1.8 $$ \times $$ 10$$-$$9 M, [Pb2+] = 1.7 $$ \times $$ 10$$-$$3 M
D
[Ag+] = 1.8 $$ \times $$ 10$$-$$11 M, [Pb2+] = 1.7 $$ \times $$ 10$$-$$4 M
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