AIPMT 2010 Mains | NEET Year Wise Previous Years Questions

AIPMT 2010 Mains

MCQ (Single Correct Answer)

-1

Match List I (substances) with List II (processes) employed in the manufacture of the substances and select the correct option.

Column $${\rm I}$$ (Substances)		Column $${\rm I}$$$${\rm I}$$ (Processes)
(A)	Sulphuric acid	(i)	Haber's process
(B)	Steel	(ii)	Bessemer's process
(C)	Sodium hydroxide	(iii)	Leblanc process
(D)	Ammonia	(iv)	Contact process

(A) $$ \to $$ (i); (B) $$ \to $$ (iv); (C) $$ \to $$ (ii); (D) $$ \to $$ (iii)

(A) $$ \to $$ (i); (B) $$ \to $$ (ii); (C) $$ \to $$ (iii); (D) $$ \to $$ (iv)

(A) $$ \to $$ (iv); (B) $$ \to $$ (iii); (C) $$ \to $$ (ii); (D) $$ \to $$ (i)

(A) $$ \to $$ (iv); (B) $$ \to $$ (ii); (C) $$ \to $$ (iii); (D) $$ \to $$ (i)

AIPMT 2010 Mains

MCQ (Single Correct Answer)

-1

How many bridging oxygen atoms are present in P₄O₁₀?

AIPMT 2010 Mains

MCQ (Single Correct Answer)

-1

The rate of the reaction, 2NO + Cl₂ $$ \to $$ 2NOCl is given by the rate equation rate = k[NO]²[Cl₂]. The value of the rate constant can be increased by

increasing the temperature

increasing the concentration of NO

increasing the concentration of the Cl₂

doing all of these.

AIPMT 2010 Mains

MCQ (Single Correct Answer)

-1

Consider the following relations for emf of an electrochemical cell
(i) EMF of cell = (Oxidation potential of anode) $$-$$ (Reduction potential of cathode)
(ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode)
(iii) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode)
(iv) EMF of cell = (Oxidation potential of anode) $$-$$ (Oxidation potential of cathode)

Which of the above relations are correct?

(iii) and (i)

(i) and (ii)

(iii) and (iv)

(ii) and (iv)

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