AIPMT 2002 | NEET Year Wise Previous Years Questions

Two bar magnets having same geometry with magnetic moments M and 2M, are firstly placed in such a way that their similar poles are same side then its time period of oscillation is T₁. Now the polarity of one of the magnet is reversed then time period of oscillation is T₂, then

T₁ < T₂

T₁ = T₂

T₁ > T₂

T₂ = $$\infty $$

AIPMT 2002

MCQ (Single Correct Answer)

-1

A wave travelling in positive X-direction with a $$=$$ 0.2 ms^$$-$$2, velocity = 360 ms^$$-$$1 and $$\lambda $$ $$=$$ 60 m, then correct expression for the wave is

$$y = 0.2\sin \left[ {2\pi \left( {6t + {x \over {60}}} \right)} \right]$$

$$y = 0.2\sin \left[ {\pi \left( {6t + {x \over {60}}} \right)} \right]$$

$$y = 0.2\sin \left[ {2\pi \left( {6t - {x \over {60}}} \right)} \right]$$

$$y = 0.2\sin \left[ {\pi \left( {6t - {x \over {60}}} \right)} \right]$$

AIPMT 2002

MCQ (Single Correct Answer)

-1

For a cell terminal potential difference is 2.2V when circuit is open and reduce to 1.8 V when cell is connected to a resistance of R = 5 $$\Omega $$. Determine internal resistance of cell (r)

$${{10} \over 9}\Omega $$

$${{9} \over 10}\Omega $$

$${{11} \over 9}\Omega $$

$${{5} \over 9}\Omega $$

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