1
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $$A B C$$ with usual notations, if $$\frac{\cos A}{a}=\frac{\cos B}{b}=\frac{\cos C}{c}$$, then area of triangle $$A B C$$ with $$a=\sqrt{6}$$ is

A
$$\frac{2}{\sqrt{3}}$$ sq units
B
$$\frac{3 \sqrt{3}}{2}$$ sq units
C
$$\frac{5 \sqrt{3}}{2}$$ sq units
D
$$\frac{\sqrt{3}}{2}$$ sq units
2
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\frac{x}{\sqrt{1+x}}+\frac{y}{\sqrt{1+y}}=0, x \neq y$$, then $$(1+x)^2 \frac{d y}{d x}=$$

A
1
B
$$\frac{1}{2}$$
C
$$-$$1
D
0
3
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$\int \frac{\sin \theta}{\sin 3 \theta} d \theta=\frac{1}{2 k} \log \left|\frac{k+\tan \theta}{k-\tan \theta}\right|+c$$, then $$k=$$

A
$$\sqrt{7}$$
B
$$\sqrt{5}$$
C
$$\sqrt{2}$$
D
$$\sqrt{3}$$
4
MHT CET 2020 16th October Morning Shift
MCQ (Single Correct Answer)
+2
-0

The probability that bomb will miss the target is 0.2. Then, the probability that out of 10 bombs dropped exactly 2 will hit the target is

A
$$\frac{288}{5^9}$$
B
$$\frac{144}{5^{10}}$$
C
$$\frac{288}{5^{10}}$$
D
$$\frac{144}{5^9}$$
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