MHT CET 2020 16th October Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

The ratio of speed of an electron in the ground state in the Bohr's first orbit of hydrogen atom to velocity of light $$(c)$$ is ( $$h=$$ Planck's constant, $$\varepsilon_0=$$ permittivity of free space, $$e=$$ charge on electron)

$$\frac{2 \theta^2 \varepsilon_0}{h c}$$

$$\frac{e^3}{2 \varepsilon_0 h c}$$

$$\frac{e^2}{2 \varepsilon_0 h c}$$

$$\frac{2 \varepsilon_0 h c}{e^2}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

A charge $$q$$ moves with velocity $$v$$ through electric field $$\mathrm{E}$$ as well as magnetic field (B). Then, the force acting on it is

$$q(E \times v)$$

$$q(B \times v)$$

$$q E+q(v \times B)$$

$$q(v \times B)$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

The force acting on the electrons in hydrogen atom (Bohr's theory) is related to the principle quantum number $$n$$ as

$$n^{-4}$$

$$n^4$$

$$n^{-2}$$

$$n^2$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

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A body of mass $$2 \mathrm{~kg}$$ is acted upon by two forces each of magnitude $$1 \mathrm{~N}$$ and inclined at $$60^{\circ}$$ with each other. The acceleration of the body in $$\mathrm{m} / \mathrm{s}$$ is [$$\cos 60^{\circ}=0.5$$]

$$\sqrt{0.75}$$

$$\sqrt{0.65}$$

$$\sqrt{0.20}$$

$$\sqrt{0.35}$$

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