1
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
$\lim _\limits{x \rightarrow 1} \frac{(\sqrt{x}-1)(2 x-3)}{2 x^2+x-3}$ is
A
$\frac{1}{10}$
B
0
C
1
D
$-\frac{1}{10}$
2
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
A circular coil of area $2 \sqrt{2} \mathrm{~cm}^2$ and resistance $2 \boldsymbol{\Omega}$ is arranged vertically in the east -west direction. A uniform magnetic field 0.2 T is set up across the plane in the north to east direction. Now the magnetic field is removed at a steady rate in 0.4 s What is the current developed in the coil?
A
$0.5 \times 10^{-3} A$
B
$0.5 \times 10^{-4} A$
C
$1 \times 10^{-4} A$
D
$0.5 \times 10^{-5} A$
3
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
A car, starting from rest, accelerates at the rate (f) through a distance ( $S$ ), then continues at constant speed for some time $(t)$ and then decelerates at the rate $\frac{f}{2}$ to come to rest. If the total distance is $5 S$, then
A
$S=\frac{1}{4} f t^2$
B
$S=\frac{1}{2} f t^2$
C
$S=4 f t^2$
D
$S=2 f t^2$
4
COMEDK 2025 Afternoon Shift
MCQ (Single Correct Answer)
+1
-0
A particle ' X ' carrying a charge +Q is moving in a circular path of radius R around another particle ' Y ' having a charge -Q with a frequency ' $v$ '. Then the mass ' $m$ ' of the charged particle is
A
$M=\frac{Q^2}{\left[16 \pi^3 \varepsilon_0 R^3 v^2\right]}$
B
$M=\frac{Q^2}{\left[16 \pi^2 \varepsilon_0 R v^2\right]}$
C
$M=\frac{Q^2}{\left[16 \pi^2 \varepsilon_0 R^3 v^2\right]}$
D
$M=\frac{Q^2}{\left[16 \pi^3 \varepsilon_0 R^2 v^2\right]}$
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