1
KCET 2017
MCQ (Single Correct Answer)
+1
-0
The distance of the point $(-2,4,-5)$ from the line $\frac{x+3}{3}=\frac{y-4}{5}=\frac{z+8}{6}$ is
A
$\sqrt{\frac{37}{10}}$
B
$\frac{37}{10}$
C
$\frac{\sqrt{37}}{10}$
D
$\frac{37}{\sqrt{10}}$
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