1
BITSAT 2023
+3
-1

When a string is divided into four segments of $$l_1, l_2, l_3$$ and $$l_4$$. The fundamental frequencies of these three segments are $$v_1, v_2, v_3$$ and $$v_4$$, respectively. The original fundamental frequency $$(v)$$ of the string is

A
$$\sqrt{v}=\sqrt{v_1}+\sqrt{v_2}+\sqrt{v_3}+\sqrt{4}$$
B
$$v=v_1+v_2+v_3+v_4$$
C
$$1 / v=1 / v_1+1 / v_2+1 / v_3+1 / v_4$$
D
$$\frac{1}{\sqrt{v}}=\frac{1}{\sqrt{v_1}}+\frac{1}{\sqrt{v_2}}+\frac{1}{\sqrt{v_3}}+\frac{1}{\sqrt{v_4}}$$
2
BITSAT 2022
+3
-1

In a resonance coloum first and second resonance are obtained at depths 24 cm and 78 cm the third resonance will be obtained at depth.

A
160 m
B
132 m
C
131 m
D
152 m
3
BITSAT 2022
+3
-1

A submarine A travelling at 17 m/s is being chased along the line of its velocity by another submarine B travelling at 34 m/s. B sends a sonar signal of 600 Hz to detect A and receives a reflected sound of frequency $$\nu$$. The of $$\nu$$ is

[Speed of sound in water = 1500 ms$$-$$1]

A
613.7 Hz
B
6137 Hz
C
62 Hz
D
539 Hz
4
BITSAT 2022
+3
-1

Transverse waves of the same frequency are generated in two steel wires A and B. The diameter of A is twice that of B and the tension in A is half that in B. The ratio of the velocities of the waves in A and B is

A
1 : 2
B
1 : $$\sqrt2$$
C
1 : 2$$\sqrt2$$
D
3 : 2$$\sqrt2$$
EXAM MAP
Medical
NEET