1
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1

The vibrations of a string of length 60 cm fixed at both ends are represented by the equation

$$y = 4\sin \left( {{{\pi x} \over {15}}} \right)\cos (96\pi t)$$

where x and y are in cm and t is in second. Calculate the velocity of the particle at x = 7.5 cm at t = 0.25 s.

A
4 m/s
B
0
C
16 m/s
D
9.8 m/s
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