1
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

The fundamental frequency of an open organ pipe is $$600 \mathrm{~Hz}$$. The first overtone of this pipe has same frequency as first overtone of a closed organ pipe. If speed of sound is $$330 \mathrm{~m} / \mathrm{s}$$, then the length of a closed organ pipe is

A
21 cm
B
37 cm
C
31 cm
D
80 cm
2
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

The wavelength of two waves are 40 and $$42 \mathrm{~cm}$$ respectively. If the temperature of the room is $$20^{\circ} \mathrm{C}$$ then what will be the number of beats produced per second by these waves. When the speed of sound at $$0^{\circ} \mathrm{C}$$ is $$332 \mathrm{~m} / \mathrm{s}$$ ?

A
34
B
38
C
44
D
None of these
3
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

When a string is divided into four segments of $$l_1, l_2, l_3$$ and $$l_4$$. The fundamental frequencies of these three segments are $$v_1, v_2, v_3$$ and $$v_4$$, respectively. The original fundamental frequency $$(v)$$ of the string is

A
$$\sqrt{v}=\sqrt{v_1}+\sqrt{v_2}+\sqrt{v_3}+\sqrt{4}$$
B
$$v=v_1+v_2+v_3+v_4$$
C
$$1 / v=1 / v_1+1 / v_2+1 / v_3+1 / v_4$$
D
$$\frac{1}{\sqrt{v}}=\frac{1}{\sqrt{v_1}}+\frac{1}{\sqrt{v_2}}+\frac{1}{\sqrt{v_3}}+\frac{1}{\sqrt{v_4}}$$
4
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

In a resonance coloum first and second resonance are obtained at depths 24 cm and 78 cm the third resonance will be obtained at depth.

A
160 m
B
132 m
C
131 m
D
152 m
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