The equation of the plane through the points $$(2,1,0),(3,2,-2)$$ and $$(3,1,7)$$ is

The point of intersection of the line $$x+1=\frac{y+3}{3}=\frac{-z+2}{2}$$ with the plane $$3 x+4 y+5 z=10$$ is

If $$(2,3,-1)$$ is the foot of the perpendicular from $$(4,2,1)$$ to a plane, then the equation of the plane is

The octant in which the point (2, $$-$$4, $$7$$) lies is