1
KCET 2022
MCQ (Single Correct Answer)
+1
-0

The distance of the point whose position vector is $$(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}})$$ from the plane $$\mathbf{r} \cdot(\hat{\mathbf{i}}-2 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})=4$$ is

A
$$\frac{8}{\sqrt{21}}$$
B
$$8 \sqrt{21}$$
C
$$-\frac{8}{\sqrt{21}}$$
D
$$-\frac{8}{21}$$
2
KCET 2021
MCQ (Single Correct Answer)
+1
-0

The equation of the line joining the points $$(-3,4,11)$$ and $$(1,-2,7)$$ is

A
$$\frac{x+3}{2}=\frac{y-4}{3}=\frac{z-11}{4}$$
B
$$\frac{x+3}{-2}=\frac{y-4}{3}=\frac{z-11}{2}$$
C
$$\frac{x+3}{-2}=\frac{y+4}{3}=\frac{z+11}{4}$$
D
$$\frac{x+3}{2}=\frac{y+4}{-3}=\frac{z+11}{2}$$
3
KCET 2021
MCQ (Single Correct Answer)
+1
-0

The angle between the lines whose direction cosines are $$\left(\frac{\sqrt{3}}{4}, \frac{1}{4}, \frac{\sqrt{3}}{2}\right)$$ and $$\left(\frac{\sqrt{3}}{4}, \frac{1}{4}, \frac{-\sqrt{3}}{2}\right)$$

A
$$\pi$$
B
$$\frac{\pi}{2}$$
C
$$\frac{\pi}{3}$$
D
$$\frac{\pi}{4}$$
4
KCET 2021
MCQ (Single Correct Answer)
+1
-0

If a plane meets the coordinate axes at $$A, B$$ and $$C$$ in such a way that the centroid of $$\triangle A B C$$ is at the point $$(1,2,3)$$, then the equation of the plane is

A
$$\frac{x}{1}+\frac{y}{2}+\frac{z}{3}=1$$
B
$$\frac{x}{3}+\frac{y}{6}+\frac{z}{9}=1$$
C
$$\frac{x}{1}+\frac{y}{2}+\frac{z}{3}=\frac{1}{3}$$
D
$$\frac{x}{1}-\frac{y}{2}+\frac{z}{3}=-1$$
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