1
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1

Based on the provided velocity-time graph for an object’s straight-line movement, determine the total distance covered and the average speed between t = 0 and t = 20 seconds.

BITSAT 2020 Physics - Motion Question 3 English

A
0, 0
B
120 m, 60 m
C
60 m, 0
D
0, 60 m
2
BITSAT 2020
MCQ (Single Correct Answer)
+3
-1

The acceleration of a particle in m/s2 is given by a = (3t2 $$-$$ 2t + 1), where t is in second. If the particle starts with a velocity v = 1 m/s at t = 1s, then velocity of the particle at the end of 4s is

A
40 m/s
B
52 m/s
C
48 m/s
D
84 m/s
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