1
BITSAT 2021
+3
-1

A man walks in a straight line for 5 min with a velocity of 45 m/s. What is the speed with which he has to move in order to comeback to its original position in 1.5 min?

A
90 m/s
B
150 m/s
C
135 m/s
D
115 m/s
2
BITSAT 2021
+3
-1

A projectile is given an initial velocity of $$(\widehat i + \widehat j)$$ m/s, where, $$\widehat i$$ is along the ground and $$\widehat j$$ is along the vertical. If g = 10 m/s2, then the equation of its trajectory is

A
y = x + 5x2
B
y = x $$-$$ 5x2
C
y = x2 + 5x
D
y = x2 $$-$$ 5x
3
BITSAT 2020
+3
-1

Based on the provided velocity-time graph for an object’s straight-line movement, determine the total distance covered and the average speed between t = 0 and t = 20 seconds.

A
0, 0
B
120 m, 60 m
C
60 m, 0
D
0, 60 m
4
BITSAT 2020
+3
-1

The acceleration of a particle in m/s2 is given by a = (3t2 $$-$$ 2t + 1), where t is in second. If the particle starts with a velocity v = 1 m/s at t = 1s, then velocity of the particle at the end of 4s is

A
40 m/s
B
52 m/s
C
48 m/s
D
84 m/s
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