Find the value of $$\int_0^1 \frac{\log (1+x)}{1+x^2} d x$$ is

The value of $$\int_{-\pi / 2}^{\pi / 2} \frac{\cos x}{1+e^x} d x$$ is

$$\int_\limits{-3}^3 \cot ^{-1} x d x=$$

$$\int_\limits0^2\left[x^2\right] d x=$$