1
KCET 2023
+1
-0

A body is moving along a straight line with initial velocity $$v_0$$. Its acceleration $$a$$ is constant. After $$t$$ seconds, its velocity becomes $$v$$. The average velocity of the body over the given time interval is

A
$$\bar{v}=\frac{v^2-v_0^2}{a t}$$
B
$$\bar{v}=\frac{v^2+v_0^2}{2 a t}$$
C
$$\bar{v}=\frac{v^2+v_0^2}{a t}$$
D
$$\bar{v}=\frac{v^2-v_0^2}{2 a t}$$
2
KCET 2022
+1
-0

The displacement $$x$$ (in $$\mathrm{m}$$) of a particle of mass $$m$$ (in $$\mathrm{kg}$$) moving in one dimension under the action of a force, is related to time $$t$$ (in sec) by $$t=\sqrt{x}+3$$. The displacement of the particle when its velocity is zero, will be

A
zero
B
6 m
C
2 m
D
4 m
3
KCET 2022
+1
-0

Two objects are projected at an angle $$\theta^{\circ}$$ and $$\left(90-\theta^{\circ}\right)$$, to the horizontal with the same speed. The ratio of their maximum vertical heights is

A
$$\tan \theta: 1$$
B
$$1: \tan \theta$$
C
$$\tan ^2 \theta: 1$$
D
$$1: 1$$
4
KCET 2021
+1
-0

For a body moving along a straight line, the following $$v$$-$$t$$ graph is obtained.

According to the graph, the displacement during

A
uniform acceleration is greater than that during uniform motion
B
uniform acceleration is less than that during uniform motion
C
uniform acceleration is equal to that during uniform motion
D
uniform motion is zero
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