1
KCET 2026
MCQ (Single Correct Answer)
+1
-0
A mass of $1$ kg is executing SHM. Its displacement is given by $x = 6.0\cos(100t + \pi/4)$ cm. What is the maximum kinetic energy?
A
$3$ J
B
$6$ J
C
$9$ J
D
$18$ J
2
KCET 2025
MCQ (Single Correct Answer)
+1
-0

The variations of kinetic energy $K(x)$, potential energy $U(x)$ and total energy as a function of displacement of a particle in SHM is as shown in the figure. The value of $\left|x_0\right|$ is

KCET 2025 Physics - Simple Harmonic Motion Question 2 English
A
2 A
B
$\frac{\mathrm{A}}{\sqrt{2}}$
C
$\sqrt{2} \mathrm{~A}$
D
$\frac{\mathrm{A}}{2}$
3
KCET 2024
MCQ (Single Correct Answer)
+1
-0

For a particle executing simple harmonic motion (SHM), at its mean position

A
velocity is zero and acceleration is maximum.
B
velocity is maximum and acceleration is zero.
C
both velocity and acceleration are maximum.
D
both velocity and acceleration are zero.
4
KCET 2023
MCQ (Single Correct Answer)
+1
-0

A block of mass $$m$$ is connected to a light spring of force constant $$k$$. The system is placed inside a damping medium of damping constant $$b$$. The instantaneous values of displacement, acceleration and energy of the block are $$x, a$$ and $$E$$ respectively. The initial amplitude of oscillation is $$A$$ and $$\omega^{\prime}$$ is the angular frequency of oscillations. The incorrect expression related to the damped oscillations is

A
$$x=A e^{-\frac{b}{m}} \cos \left(\omega^{\prime} t+\phi\right)$$
B
$$\omega^{\prime}=\sqrt{\frac{k}{m}-\frac{b^2}{4 m^2}}$$
C
$$E=\frac{1}{2} k A^2 e^{-\frac{b t}{m}}$$
D
$$m \frac{d^2 x}{d t^2}+b \frac{d x}{d t}+k x=0$$

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