KCET 2025 | Simple Harmonic Motion Question 1 | Physics

The variations of kinetic energy $K(x)$, potential energy $U(x)$ and total energy as a function of displacement of a particle in SHM is as shown in the figure. The value of $\left|x_0\right|$ is

KCET 2025 Physics - Simple Harmonic Motion Question 1 English

2 A

$\frac{\mathrm{A}}{\sqrt{2}}$

$\sqrt{2} \mathrm{~A}$

$\frac{\mathrm{A}}{2}$

KCET 2024

MCQ (Single Correct Answer)

-0

For a particle executing simple harmonic motion (SHM), at its mean position

velocity is zero and acceleration is maximum.

velocity is maximum and acceleration is zero.

both velocity and acceleration are maximum.

both velocity and acceleration are zero.

KCET 2023

MCQ (Single Correct Answer)

-0

A block of mass $$m$$ is connected to a light spring of force constant $$k$$. The system is placed inside a damping medium of damping constant $$b$$. The instantaneous values of displacement, acceleration and energy of the block are $$x, a$$ and $$E$$ respectively. The initial amplitude of oscillation is $$A$$ and $$\omega^{\prime}$$ is the angular frequency of oscillations. The incorrect expression related to the damped oscillations is

$$x=A e^{-\frac{b}{m}} \cos \left(\omega^{\prime} t+\phi\right)$$

$$\omega^{\prime}=\sqrt{\frac{k}{m}-\frac{b^2}{4 m^2}}$$

$$E=\frac{1}{2} k A^2 e^{-\frac{b t}{m}}$$

$$m \frac{d^2 x}{d t^2}+b \frac{d x}{d t}+k x=0$$

KCET 2022

MCQ (Single Correct Answer)

-0

The displacement of a particle executing SHM is given by $$x=3 \sin \left[2 \pi t+\frac{\pi}{4}\right]$$, where $$x$$ is in metre and $$t$$ is in seconds. The amplitude and maximum speed of the particles is

$$3 \mathrm{~m}, 4 \pi \mathrm{ms}^{-1}$$

$$3 \mathrm{~m}, 6 \pi \mathrm{ms}^{-1}$$

$$3 \mathrm{~m}, 8 \pi \mathrm{ms}^{-1}$$

$$3 \mathrm{~m}, 2 \pi \mathrm{ms}^{-1}$$

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