1
KCET 2025
MCQ (Single Correct Answer)
+1
-0
Which of the following expression can be deduced on the basis of dimensional analysis? (All symbols have their usual meanings)
A
$\mathrm{x}=\mathrm{A} \cos \omega \mathrm{t}$
B
$\mathrm{N}=\mathrm{N}_0 \mathrm{e}^{-\lambda \mathrm{t}}$
C
$\mathrm{F}=6 \pi \eta \mathrm{r} \nu$
D
$\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}{ }^2$
2
KCET 2024
MCQ (Single Correct Answer)
+1
-0

Dimensional formula for activity of a radioactive substance is

A
$\left[M^0 \mathrm{~L}^1 \mathrm{~T}^{-1}\right]$
B
$\left[M^0 L^{-1} T^0\right]$
C
$\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]$
D
$\left[M^{-1} L^0 T^0\right]$
3
KCET 2023
MCQ (Single Correct Answer)
+1
-0

The true length of a wire is $$3.678 \mathrm{~cm}$$. When the length of this wire is measured using instrument $$A$$, the length of the wire is $$3.5 \mathrm{~cm}$$. When the length of the wire is measured using instrument $$B$$, it is found to have length $$3.38 \mathrm{~cm}$$. Then, the

A
measurement with $$A$$ is more accurate and precise.
B
measurement with $$A$$ is more accurate while measurement with $$B$$ is more precise.
C
measurement with $$B$$ is more accurate and precise.
D
measurement with $$A$$ is more precise while measurement with $$B$$ is more constant.
4
KCET 2022
MCQ (Single Correct Answer)
+1
-0

The Vernier scale of a travelling microscope has 50 divisions which coincides with 49 main scale divisions. If each main scale division is $$0.5 \mathrm{~mm}$$, then the least count of the microscope is

A
$$0.5 \mathrm{~mm}$$
B
$$0.01 \mathrm{~mm}$$
C
$$0.5 \mathrm{~cm}$$
D
$$0.01 \mathrm{~cm}$$
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