KCET 2026 | Units & Measurement and Dimensions Question 1 | Physics

Match the physical quantities given in List-I with dimensions expressed in terms of mass (M), length (L), time (T) and electric current (A) given in List-II.

List-I	List-II
(a) Torque	(i) $[M^{-1}L^{-2}T^{4}A^{2}]$
(b) Gravitational constant	(ii) $[M^{1}L^{2}T^{-1}]$
(c) Capacitance	(iii) $[M^{-1}L^{3}T^{-2}]$
(d) Planck's constant	(iv) $[M^{1}L^{2}T^{-2}]$

Codes:

a - iv, b - ii, c - iii, d – i

a - iv, b - iii, c - i, d – ii

a - iv, b - i, c - iii, d – ii

a - ii, b - i, c - iii, d – iv

KCET 2025

MCQ (Single Correct Answer)

-0

Which of the following expression can be deduced on the basis of dimensional analysis? (All symbols have their usual meanings)

$\mathrm{x}=\mathrm{A} \cos \omega \mathrm{t}$

$\mathrm{N}=\mathrm{N}_0 \mathrm{e}^{-\lambda \mathrm{t}}$

$\mathrm{F}=6 \pi \eta \mathrm{r} \nu$

$\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}{ }^2$

KCET 2024

MCQ (Single Correct Answer)

-0

Dimensional formula for activity of a radioactive substance is

$\left[M^0 \mathrm{~L}^1 \mathrm{~T}^{-1}\right]$

$\left[M^0 L^{-1} T^0\right]$

$\left[\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}\right]$

$\left[M^{-1} L^0 T^0\right]$

KCET 2023

MCQ (Single Correct Answer)

-0

The true length of a wire is $$3.678 \mathrm{~cm}$$. When the length of this wire is measured using instrument $$A$$, the length of the wire is $$3.5 \mathrm{~cm}$$. When the length of the wire is measured using instrument $$B$$, it is found to have length $$3.38 \mathrm{~cm}$$. Then, the

measurement with $$A$$ is more accurate and precise.

measurement with $$A$$ is more accurate while measurement with $$B$$ is more precise.

measurement with $$B$$ is more accurate and precise.

measurement with $$A$$ is more precise while measurement with $$B$$ is more constant.

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