1
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Consider the function $$\mathrm{f}(x)=(x-2) \log _{\mathrm{e}} x$$. Then the equation $$x \log _{\mathrm{e}} x=2-x$$

A
has at least one root in $$(1,2)$$
B
has no root in $$(1,2)$$
C
is not at all solvable
D
has infinitely many roots in $$(-2,1)$$
2
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $$\alpha, \beta$$ are the roots of the equation $$a x^2+b x+c=0$$ then $$\lim _\limits{x \rightarrow \beta} \frac{1-\cos \left(a x^2+b x+c\right)}{(x-\beta)^2}$$ is

A
$$(\alpha-\beta)^2$$
B
$$\frac{1}{2}(\alpha-\beta)^2$$
C
$$\frac{a^2}{4}(\alpha-\beta)^2$$
D
$$\frac{\mathrm{a}^2}{2}(\alpha-\beta)^2$$
3
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $$\mathrm{f}(x)=\frac{\mathrm{e}^x}{1+\mathrm{e}^x}, \mathrm{I}_1=\int_\limits{\mathrm{f}(-\mathrm{a})}^{\mathrm{f}(\mathrm{a})} x \mathrm{~g}(x(1-x)) \mathrm{d} x$$ and $$\mathrm{I}_2=\int_\limits{\mathrm{f}(-\mathrm{a})}^{\mathrm{f}(\mathrm{a})} \mathrm{g}(x(1-x)) \mathrm{d} x$$, then the value of $$\frac{I_2}{I_1}$$ is

A
$$-1$$
B
$$-3$$
C
2
D
1
4
WB JEE 2024
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Let $$f: \mathbb{R} \rightarrow \mathbb{R}$$ be a differentiable function and $$f(1)=4$$. Then the value of $$\lim _\limits{x \rightarrow 1} \int_\limits4^{f(x)} \frac{2 t}{x-1} d t$$, if $$f^{\prime}(1)=2$$ is

A
16
B
8
C
4
D
2
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