1
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $\bar{a}=(2 \hat{i}+2 \hat{j}+3 \hat{k}), \vec{b}=(-\hat{i}+2 \hat{j}+\hat{k}) \quad$ and $\bar{c}=(3 \hat{i}+\hat{j})$ such that $(\bar{a}+\lambda \bar{b})$ is perpendicular to $\bar{c}$, then the value of $\lambda$ is

A
$-8$
B
8
C
10
D
$\frac{8}{3}$
2
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The solution of the differential equation $\frac{\mathrm{d} y}{\mathrm{~d} x}=(x-y)^2$ when $y(1)=1$ is

A
$\log \left|\frac{2-y}{2-x}\right|=2(y-1)$
B
$-\log \left|\frac{1+x-y}{1-x+y}\right|=x+y-2$
C
$\log \left|\frac{2-x}{2-y}\right|=x-y$
D
$-\log \left|\frac{1-+xy}{1+x-y}\right|=2(x-1)$
3
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $x_0$ is the point of local minima of $f(x)=\overline{\mathrm{a}} \cdot(\overline{\mathrm{b}} \times \overline{\mathrm{c}})$ where $\overline{\mathrm{a}}=x \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}$, $\overline{\mathrm{b}}=-2 \hat{\mathrm{i}}+x \hat{\mathrm{j}}-\hat{\mathrm{k}}, \overline{\mathrm{c}}=7 \hat{\mathrm{i}}-2 \hat{\mathrm{j}}+x \hat{\mathrm{k}}$, then value of $\overline{\mathrm{a}} \cdot \overline{\mathrm{b}}$ at $x=x_0$ is

A
$-3$
B
$-15$
C
$-12$
D
$-9$
4
MHT CET 2024 2nd May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$\hat{a}, \hat{b}$, and $\hat{c}$ are three unit vectors such that $\hat{a} \times(\hat{b} \times \hat{c})=\frac{\sqrt{3}}{2}(\hat{b}+\hat{c})$. If $\dot{b}$ is not parallel to $\hat{c}$, then the angle between $\hat{a}$ and $\hat{b}$ is

A
$\frac{5 \pi}{6}$
B
$\frac{\pi}{6}$
C
$\frac{\pi}{3}$
D
$\frac{2 \pi}{3}$
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