MHT CET 2023 13th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

The incentre of the $$\triangle A B C$$, whose vertices are $$A(0,2,1), B(-2,0,0)$$ and $$C(-2,0,2)$$, is

$$\left(-\frac{3}{2}, \frac{1}{2}, 1\right)$$

$$\left(\frac{3}{2}, \frac{1}{2}, 1\right)$$

$$\left(-\frac{3}{2},-\frac{1}{2},-1\right)$$

$$\left(\frac{3}{2},-\frac{1}{2},-1\right)$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

The acute angle between the line joining the points $$(2,1,-3),(-3,1,7)$$ and a line parallel to $$\frac{x-1}{3}=\frac{y}{4}=\frac{z+3}{5}$$ through the point $$(-1,0,4)$$ is

$$\cos ^{-1}\left(\frac{1}{\sqrt{10}}\right)$$

$$\cos ^{-1}\left(\frac{5}{7 \sqrt{10}}\right)$$

$$\cos ^{-1}\left(\frac{7}{5 \sqrt{10}}\right)$$

$$\cos ^{-1}\left(\frac{3}{5 \sqrt{10}}\right)$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

A random variable $$X$$ has the probability distribution

$$X=x$$	1	2	3	4	5	6	7	8
$$P(X=x)$$	0.15	0.23	0.12	0.20	0.08	0.10	0.05	0.07

For the events $$E=\{X$$ is a prime number $$\}$$ and $$F=\{x<5\}, P(E U F)$$ is

0.63

0.75

0.83

0.90

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

The shaded area in the given figure is a solution set for some system of inequations. The maximum value of the function $$z=10 x+25 y$$ subject to the linear constraints given by the system is

MHT CET 2023 13th May Evening Shift Mathematics - Linear Programming Question 31 English