1
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The work done in rotating a dipole placed parallel to the electric field through $$180^{\circ}$$ is W. So, the work done in rotating it through $$60^{\circ}$$ is $$\left(\cos 0^{\circ}=1, \cos 60^{\circ}=\frac{1}{2}, \cos 180^{\circ}=-1\right)$$

A
$$4 W$$
B
$$3 \mathrm{~W}$$
C
$$W / 2$$
D
$$W / 4$$
2
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

When an electron is excited from its 4 th orbit to 5 th stationary orbit, the change in the angular momentum of electron is approximately.

(Planck's constant $$=h=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$ )

A
$$2 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
B
$$6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
C
$$1 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
D
$$3.14 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$
3
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

The Boolean expression for the following combination is

MHT CET 2023 13th May Evening Shift Physics - Semiconductor Devices and Logic Gates Question 36 English

A
$$(\overline{A+B}) \cdot(A+B)$$
B
$$(\overline{A \cdot B})+(\bar{A} \cdot {B})$$
C
$$(\bar{A} \cdot B)+(A \cdot \bar{B})$$
D
$$(\bar{A}+B) \cdot(A+\bar{B})$$
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+1
-0

Under the influence of force $$F_1$$ the body oscillates with a period $$T_1$$ and due to another force $$F_2$$ body oscillates with period $$T_2$$. If both forces acts simultaneously, then the resultant period is (consider displacement is same in all three cases)

A
$$T=\sqrt{\frac{T_1^2+T_2^2}{T_1^2 T_2^2}}$$
B
$$T=\sqrt{\frac{T_1^2 T_2^2}{T_1^2+T_2^2}}$$
C
$$T=\sqrt{\frac{T_1^2}{T_2^2}}$$
D
$$T=\sqrt{T_1^2+T_2^2}$$
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