MHT CET 2023 13th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

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When an electron is excited from its 4 th orbit to 5 th stationary orbit, the change in the angular momentum of electron is approximately.

(Planck's constant $$=h=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$ )

$$2 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$

$$6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$

$$1 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$

$$3.14 \times 10^{-34} \mathrm{~J}-\mathrm{s}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

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The Boolean expression for the following combination is

MHT CET 2023 13th May Evening Shift Physics - Semiconductor Devices and Logic Gates Question 78 English

$$(\overline{A+B}) \cdot(A+B)$$

$$(\overline{A \cdot B})+(\bar{A} \cdot {B})$$

$$(\bar{A} \cdot B)+(A \cdot \bar{B})$$

$$(\bar{A}+B) \cdot(A+\bar{B})$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

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Under the influence of force $$F_1$$ the body oscillates with a period $$T_1$$ and due to another force $$F_2$$ body oscillates with period $$T_2$$. If both forces acts simultaneously, then the resultant period is (consider displacement is same in all three cases)

$$T=\sqrt{\frac{T_1^2+T_2^2}{T_1^2 T_2^2}}$$

$$T=\sqrt{\frac{T_1^2 T_2^2}{T_1^2+T_2^2}}$$

$$T=\sqrt{\frac{T_1^2}{T_2^2}}$$

$$T=\sqrt{T_1^2+T_2^2}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

The internal energy of a monoatomic ideal gas molecule is

partly kinetic and partly potential

totally kinetic

totally potential

Neither kinetic nor potential